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8^2=8x^2
We move all terms to the left:
8^2-(8x^2)=0
We add all the numbers together, and all the variables
-8x^2+64=0
a = -8; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-8)·64
Δ = 2048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2048}=\sqrt{1024*2}=\sqrt{1024}*\sqrt{2}=32\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{2}}{2*-8}=\frac{0-32\sqrt{2}}{-16} =-\frac{32\sqrt{2}}{-16} =-\frac{2\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{2}}{2*-8}=\frac{0+32\sqrt{2}}{-16} =\frac{32\sqrt{2}}{-16} =\frac{2\sqrt{2}}{-1} $
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